(8x-5)(2x^2-9x-5)=0

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Solution for (8x-5)(2x^2-9x-5)=0 equation: 


Simplifying
(8x + -5)(2x2 + -9x + -5) = 0

Reorder the terms:
(-5 + 8x)(2x2 + -9x + -5) = 0

Reorder the terms:
(-5 + 8x)(-5 + -9x + 2x2) = 0

Multiply (-5 + 8x) * (-5 + -9x + 2x2)
(-5(-5 + -9x + 2x2) + 8x * (-5 + -9x + 2x2)) = 0
((-5 * -5 + -9x * -5 + 2x2 * -5) + 8x * (-5 + -9x + 2x2)) = 0
((25 + 45x + -10x2) + 8x * (-5 + -9x + 2x2)) = 0
(25 + 45x + -10x2 + (-5 * 8x + -9x * 8x + 2x2 * 8x)) = 0
(25 + 45x + -10x2 + (-40x + -72x2 + 16x3)) = 0

Reorder the terms:
(25 + 45x + -40x + -10x2 + -72x2 + 16x3) = 0

Combine like terms: 45x + -40x = 5x
(25 + 5x + -10x2 + -72x2 + 16x3) = 0

Combine like terms: -10x2 + -72x2 = -82x2
(25 + 5x + -82x2 + 16x3) = 0

Solving
25 + 5x + -82x2 + 16x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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